Optimal. Leaf size=109 \[ -\frac {x}{4 a^3 \left (1-a^2 x^2\right )}-\frac {\tanh ^{-1}(a x)}{4 a^4}+\frac {\tanh ^{-1}(a x)}{2 a^4 \left (1-a^2 x^2\right )}+\frac {\tanh ^{-1}(a x)^2}{2 a^4}-\frac {\tanh ^{-1}(a x) \log \left (\frac {2}{1-a x}\right )}{a^4}-\frac {\text {PolyLog}\left (2,1-\frac {2}{1-a x}\right )}{2 a^4} \]
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Rubi [A]
time = 0.12, antiderivative size = 109, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 8, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.400, Rules used = {6175, 6131,
6055, 2449, 2352, 6141, 205, 212} \begin {gather*} -\frac {\text {Li}_2\left (1-\frac {2}{1-a x}\right )}{2 a^4}+\frac {\tanh ^{-1}(a x)^2}{2 a^4}-\frac {\tanh ^{-1}(a x)}{4 a^4}-\frac {\log \left (\frac {2}{1-a x}\right ) \tanh ^{-1}(a x)}{a^4}+\frac {\tanh ^{-1}(a x)}{2 a^4 \left (1-a^2 x^2\right )}-\frac {x}{4 a^3 \left (1-a^2 x^2\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 205
Rule 212
Rule 2352
Rule 2449
Rule 6055
Rule 6131
Rule 6141
Rule 6175
Rubi steps
\begin {align*} \int \frac {x^3 \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx &=\frac {\int \frac {x \tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx}{a^2}-\frac {\int \frac {x \tanh ^{-1}(a x)}{1-a^2 x^2} \, dx}{a^2}\\ &=\frac {\tanh ^{-1}(a x)}{2 a^4 \left (1-a^2 x^2\right )}+\frac {\tanh ^{-1}(a x)^2}{2 a^4}-\frac {\int \frac {1}{\left (1-a^2 x^2\right )^2} \, dx}{2 a^3}-\frac {\int \frac {\tanh ^{-1}(a x)}{1-a x} \, dx}{a^3}\\ &=-\frac {x}{4 a^3 \left (1-a^2 x^2\right )}+\frac {\tanh ^{-1}(a x)}{2 a^4 \left (1-a^2 x^2\right )}+\frac {\tanh ^{-1}(a x)^2}{2 a^4}-\frac {\tanh ^{-1}(a x) \log \left (\frac {2}{1-a x}\right )}{a^4}-\frac {\int \frac {1}{1-a^2 x^2} \, dx}{4 a^3}+\frac {\int \frac {\log \left (\frac {2}{1-a x}\right )}{1-a^2 x^2} \, dx}{a^3}\\ &=-\frac {x}{4 a^3 \left (1-a^2 x^2\right )}-\frac {\tanh ^{-1}(a x)}{4 a^4}+\frac {\tanh ^{-1}(a x)}{2 a^4 \left (1-a^2 x^2\right )}+\frac {\tanh ^{-1}(a x)^2}{2 a^4}-\frac {\tanh ^{-1}(a x) \log \left (\frac {2}{1-a x}\right )}{a^4}-\frac {\text {Subst}\left (\int \frac {\log (2 x)}{1-2 x} \, dx,x,\frac {1}{1-a x}\right )}{a^4}\\ &=-\frac {x}{4 a^3 \left (1-a^2 x^2\right )}-\frac {\tanh ^{-1}(a x)}{4 a^4}+\frac {\tanh ^{-1}(a x)}{2 a^4 \left (1-a^2 x^2\right )}+\frac {\tanh ^{-1}(a x)^2}{2 a^4}-\frac {\tanh ^{-1}(a x) \log \left (\frac {2}{1-a x}\right )}{a^4}-\frac {\text {Li}_2\left (1-\frac {2}{1-a x}\right )}{2 a^4}\\ \end {align*}
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Mathematica [A]
time = 0.10, size = 64, normalized size = 0.59 \begin {gather*} -\frac {4 \tanh ^{-1}(a x)^2-2 \tanh ^{-1}(a x) \left (\cosh \left (2 \tanh ^{-1}(a x)\right )-4 \log \left (1+e^{-2 \tanh ^{-1}(a x)}\right )\right )-4 \text {PolyLog}\left (2,-e^{-2 \tanh ^{-1}(a x)}\right )+\sinh \left (2 \tanh ^{-1}(a x)\right )}{8 a^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.75, size = 159, normalized size = 1.46
method | result | size |
derivativedivides | \(\frac {\frac {\arctanh \left (a x \right )}{4 a x +4}+\frac {\arctanh \left (a x \right ) \ln \left (a x +1\right )}{2}-\frac {\arctanh \left (a x \right )}{4 \left (a x -1\right )}+\frac {\arctanh \left (a x \right ) \ln \left (a x -1\right )}{2}-\frac {\dilog \left (\frac {a x}{2}+\frac {1}{2}\right )}{2}-\frac {\ln \left (a x -1\right ) \ln \left (\frac {a x}{2}+\frac {1}{2}\right )}{4}+\frac {\ln \left (a x -1\right )^{2}}{8}+\frac {\left (\ln \left (a x +1\right )-\ln \left (\frac {a x}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {a x}{2}+\frac {1}{2}\right )}{4}-\frac {\ln \left (a x +1\right )^{2}}{8}+\frac {1}{8 a x +8}-\frac {\ln \left (a x +1\right )}{8}+\frac {1}{8 a x -8}+\frac {\ln \left (a x -1\right )}{8}}{a^{4}}\) | \(159\) |
default | \(\frac {\frac {\arctanh \left (a x \right )}{4 a x +4}+\frac {\arctanh \left (a x \right ) \ln \left (a x +1\right )}{2}-\frac {\arctanh \left (a x \right )}{4 \left (a x -1\right )}+\frac {\arctanh \left (a x \right ) \ln \left (a x -1\right )}{2}-\frac {\dilog \left (\frac {a x}{2}+\frac {1}{2}\right )}{2}-\frac {\ln \left (a x -1\right ) \ln \left (\frac {a x}{2}+\frac {1}{2}\right )}{4}+\frac {\ln \left (a x -1\right )^{2}}{8}+\frac {\left (\ln \left (a x +1\right )-\ln \left (\frac {a x}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {a x}{2}+\frac {1}{2}\right )}{4}-\frac {\ln \left (a x +1\right )^{2}}{8}+\frac {1}{8 a x +8}-\frac {\ln \left (a x +1\right )}{8}+\frac {1}{8 a x -8}+\frac {\ln \left (a x -1\right )}{8}}{a^{4}}\) | \(159\) |
risch | \(\frac {\ln \left (a x +1\right )^{2}}{8 a^{4}}+\frac {\ln \left (a x -1\right )}{16 a^{4}}-\frac {\ln \left (a x +1\right ) x}{16 a^{3} \left (a x -1\right )}-\frac {\ln \left (a x +1\right )}{16 a^{4} \left (a x -1\right )}+\frac {\ln \left (a x +1\right )}{8 a^{4} \left (a x +1\right )}+\frac {1}{8 a^{4} \left (a x +1\right )}+\frac {\ln \left (-\frac {a x}{2}+\frac {1}{2}\right ) \ln \left (a x +1\right )}{4 a^{4}}-\frac {\dilog \left (\frac {a x}{2}+\frac {1}{2}\right )}{4 a^{4}}-\frac {\ln \left (-a x +1\right )^{2}}{8 a^{4}}-\frac {\ln \left (-a x -1\right )}{16 a^{4}}-\frac {\ln \left (-a x +1\right ) x}{16 a^{3} \left (-a x -1\right )}+\frac {\ln \left (-a x +1\right )}{16 a^{4} \left (-a x -1\right )}-\frac {\ln \left (-a x +1\right )}{8 a^{4} \left (-a x +1\right )}-\frac {1}{8 a^{4} \left (-a x +1\right )}-\frac {\ln \left (\frac {a x}{2}+\frac {1}{2}\right ) \ln \left (-a x +1\right )}{4 a^{4}}+\frac {\dilog \left (-\frac {a x}{2}+\frac {1}{2}\right )}{4 a^{4}}\) | \(254\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.27, size = 177, normalized size = 1.62 \begin {gather*} -\frac {1}{8} \, a {\left (\frac {{\left (a^{2} x^{2} - 1\right )} \log \left (a x + 1\right )^{2} - 2 \, {\left (a^{2} x^{2} - 1\right )} \log \left (a x + 1\right ) \log \left (a x - 1\right ) - {\left (a^{2} x^{2} - 1\right )} \log \left (a x - 1\right )^{2} - 2 \, a x - {\left (a^{2} x^{2} - 1\right )} \log \left (a x - 1\right )}{a^{7} x^{2} - a^{5}} + \frac {4 \, {\left (\log \left (a x - 1\right ) \log \left (\frac {1}{2} \, a x + \frac {1}{2}\right ) + {\rm Li}_2\left (-\frac {1}{2} \, a x + \frac {1}{2}\right )\right )}}{a^{5}} + \frac {\log \left (a x + 1\right )}{a^{5}}\right )} - \frac {1}{2} \, {\left (\frac {1}{a^{6} x^{2} - a^{4}} - \frac {\log \left (a^{2} x^{2} - 1\right )}{a^{4}}\right )} \operatorname {artanh}\left (a x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x^{3} \operatorname {atanh}{\left (a x \right )}}{\left (a x - 1\right )^{2} \left (a x + 1\right )^{2}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^3\,\mathrm {atanh}\left (a\,x\right )}{{\left (a^2\,x^2-1\right )}^2} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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